Question

The area of four walls of a hall in the form of a cuboid is 220m² and height of the hall is 5m, therefore the perimeter of the floor of the hall is
1 ) 11
2)22
3)44
4) 88

Answer 1

Answer:

so the answer is 44 because when we divide 220m2 ÷5=44 is the answer

Answer 2

Answer:

Step-by-step explanation:

LSA of cuboid = 2( lb +lh + bh)

given that LSA = 220 m∧2 ; h=5m

2 (lb +5l +5b ) = 220  

lb + 5( l+b) = 440   ⇒eq.1

• if perimeter = 22m∧2,

2(l+b)=22

l+b = 11

then ,  (eq.1)

lb + 5(11)= 440

lb = 440/55 = 8  (eq.2)

l = 11-b

(11-b)×b = 11b - b∧2 = 8

11b - b∧2 - 8 =0

do x = -b +- $\sqrt b2 - 4ac$/ 2a

if u dont get the answer then try for the other options