Question

.The area of four walls of a room is{144m}^{2}144m
2
.
If the length of the room is twice its breadth and height is 4m. Find the area of the floor.​​

Answer 1

Answer:

Hello mate,

Let the breadth of the room be x meters,

Then the length of the room is 3x meters

and the height of the room is 3 meters

and it is given that area of the 4 walls=144 m square

This implies,

The lateral surface area of the room=144 m square

2(length+breadth)*height=144 m square

2(3x+x)*3m=144 m

3x+x=144/2*3

4x=24m

x=24/4=6m

So,The breadth of the room =x=6 m

and,The length of the room =3 x=3*6=18 m

So,The area of the base =length *breadth=6 m*18 m=108 m square mark brainly

Answer 2

Hey mate answer of your question is given below by me...

I don't know the breadth of room so.

Let the breadth of the room is x meters

According to the question Then the length of the room be 3x ..meters

Given height of the room is 4 meters..

As well as area of four walls given in the question is 144 square meters..

As you know...

Curved surface area of room= 144m square

2(length+breadth)× height= 144m square

2(3x+x)×4=144 m square

4x= 144/2*3m square

4x= 144/6

x= 24 /4

x= 6m square...

Breadth = 6

Then length 3x= 3*6= 18 ...

Area of floor = length * breadth

= 6*18

= 108 Meyer square.. .

I hope it can help u.....

Thanks....