Math, asked by Anonymous, 3 months ago

The area of four walls of a room is 150 ^2 m . If the length of the room is twice its breadth and the height is 4 m, find the area of the floor .​
please answer correctly don't mess up everything.


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Answers

Answered by prakriti12325
8

Answer:

427=729=427-55+25 Ok you are not working interested

Answered by ItzBackBencherHarshu
144

Given :

Area of four walls of a room = 150 m²

Height of the room = 4 m

Length of the room is twice the breadth of the room

To Find :

The Area of the floor

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Let the breadth of the room be "b" . Then the length of thr room becomes "2b' [Given condition]

Area of Four walls of a room is given by ,

\begin{gathered} \\ \star \: {\boxed{\purple{\sf{Area_{(four \: walls)} = 2(length + breadth) \times height}}}} \\ \\ \end{gathered}

Substituting the values we have ,

\begin{gathered} \\ : \implies \sf \: 150 = 2(2b + b) \times 4 \\ \\ \end{gathered}

\begin{gathered} \\ : \implies \sf \: 150 = 2(3b) \times 4 \\ \\ \end{gathered}

\begin{gathered} \\ : \implies \sf \: 150 = 6b \times 4 \\ \\ \end{gathered}

\begin{gathered} \\ : \implies \sf \: 6b = \frac{150}{4} \\ \\ \end{gathered}

\begin{gathered} \\ : \implies \sf \: 6b = 37.5 \\ \\ \end{gathered}

\begin{gathered} \\ : \implies \sf \: b = \frac{37.5}{6} \\ \\ \end{gathered}

\begin{gathered} \\ : \implies{\underline{\boxed{\blue{\mathfrak{b = 6.25 \: cm}}}}} \\ \\ \end{gathered}

So , The Breadth of the room is 6.25 cm. The the length of the room is 2(6.25) which is equal to 12.5 cm.

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Area of floor is given by ,

\begin{gathered} \\ \star \: {\boxed{\purple{\sf{Area_{(floor)} = length \times width}}}} \\ \\ \end{gathered}

Substituting the values we have ,

\begin{gathered} \\ : \implies \sf \: Area_{(floor)} = 12.5 \times 6.25 \\ \\ \end{gathered}

\begin{gathered} \\ : \implies{\underline{\boxed {\pink{\mathfrak{Area_{(floor)} = 78.125 \: {cm}^{2} }}}}} \: \bigstar \\ \\ \end{gathered}

\begin{gathered} \\ \therefore \: {\underline{\sf{Hence \: , \: The \: Area \: of \: the \: Floor \: is \: \bold{78.125 cm^2}}}}\end{gathered}

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