Question

The area of four walls of a room is 150 ^2 m . If the length of the room is twice its breadth and the height is 4 m, find the area of the floor .​ ​

Answer 1

Formula: AH = TAS

Where, AH symbolizes Enthalpy of Fusion, T represents Temperature in Kelvin and AS represent Entropy.

According to the question,

- Enthalpy of Fusion = AH = 1.435 Kcal/

mol » Enthalpy of Fusion = AH = 1435 cal/mol

It is given melting point of ice is 0°C. Converting it to Kelvin we get:

- Melting Point of Ice = 0°C + 273 = 273 K

=

Now we are required to find the value of Molar Entropy (AS)

Since AH is in terms of Calories per mole, we can directly substitute it in the formula.

Now we are required to find the value of Molar Entropy (AS)

Since AH is in terms of Calories per mole, we can directly substitute it in the formula.

1435 cal/mol = 273 K xAS

» AS = 1435 cal/mole / 273 K

» AS = 5.256 cal/mole.K

- AS = 5.26 cal/mole.K

Hence Option (1) is the correct answer.

Answer 2

Answer:

Given :

Area of four walls of a room = 150 m²

Height of the room = 4 m

Length of the room is twice the breadth of the room

To Find :

The Area of the floor

Solution :

Let the breadth of the room be "b" . Then the length of thr room becomes "2b' [Given condition]

Area of Four walls of a room is given by ,

$\\ \star \: {\boxed{\purple{\sf{Area_{(four \: walls)} = 2(length + breadth) \times height}}}}$

Substituting the values we have ,

$\\ : \implies \sf \: 150 = 2(2b + b) \times 4$

$\\ : \implies \sf \: 150 = 2(3b) \times 4$

$\\ : \implies \sf \: 150 = 6b \times 4$

$\\ : \implies \sf \: 6b = \frac{150}{4}$

$\\ : \implies \sf \: 6b = 37.5$

$\\ : \implies \sf \: b = \frac{37.5}{6}$

$\\ : \implies{\underline{\boxed{\blue{\mathfrak{b = 6.25 \: cm}}}}}$

So , The Breadth of the room is 6.25 cm. The the length of the room is 2(6.25) which is equal to 12.5 cm.

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Area of floor is given by ,

$\\ \star \: {\boxed{\purple{\sf{Area_{(floor)} = length \times width}}}}$

Substituting the values we have ,

$\\ : \implies \sf \: Area_{(floor)} = 12.5 \times 6.25$

$\\ : \implies{\underline{\boxed {\pink{\mathfrak{Area_{(floor)} = 78.125 \: {cm}^{2} }}}}} \: \bigstar$

$\\ \therefore \: {\underline{\sf{Hence \: , \: The \: Area \: of \: the \: Floor \: is \: \bold{78.125 cm^2}}}}$

Answer 3

Answer:

Given :

Area of four walls of a room = 150 m²

Height of the room = 4 m

Length of the room is twice the breadth of the room

To Find :

The Area of the floor

Solution :

Let the breadth of the room be "b" . Then the length of thr room becomes "2b' [Given condition]

Area of Four walls of a room is given by ,

$\\ \star \: {\boxed{\purple{\sf{Area_{(four \: walls)} = 2(length + breadth) \times height}}}}$

Substituting the values we have ,

$\\ : \implies \sf \: 150 = 2(2b + b) \times 4$

$\\ : \implies \sf \: 150 = 2(3b) \times 4$

$\\ : \implies \sf \: 150 = 6b \times 4$

$\\ : \implies \sf \: 6b = \frac{150}{4}$

$\\ : \implies \sf \: 6b = 37.5$

$\\ : \implies \sf \: b = \frac{37.5}{6}$

$\\ : \implies{\underline{\boxed{\blue{\mathfrak{b = 6.25 \: cm}}}}}$

So , The Breadth of the room is 6.25 cm. The the length of the room is 2(6.25) which is equal to 12.5 cm.

$\qquad$━━━━━━━━━━━━━━━

Area of floor is given by ,

$\\ \star \: {\boxed{\purple{\sf{Area_{(floor)} = length \times width}}}}$

Substituting the values we have ,

$\\ : \implies \sf \: Area_{(floor)} = 12.5 \times 6.25$

$\\ : \implies{\underline{\boxed {\pink{\mathfrak{Area_{(floor)} = 78.125 \: {cm}^{2} }}}}} \: \bigstar$

$\\ \therefore \: {\underline{\sf{Hence \: , \: The \: Area \: of \: the \: Floor \: is \: \bold{78.125 cm^2}}}}$