Question

The area of four walls of a room is 150 m2 . If the length of the room is twice its breadth an the height is 4 m, find the area of the floor. pic of the answer don't spam​

Answer 1

Answer:

78.125 sq. m.

Step-by-step explanation:

Suppose the breadth is x.

Then length = 2x

$lsa = 2h(l + b) \\ 150 = 2 \times 4(x + 2x) \\ 150 = 8 \times 3x \\ 150 = 24x \\ x = \frac{150}{24} = 6.25 \: m$

Therefore the breadth of room = x = 6.25 m

length of room = 2x = 12.5 m

Area = length × breadth = 12.5 × 6.25 = 78.125 sq. m.

Answer 2

Answer:-

• 78.125 cm²

Step-by-step explaination:-

Given:-

• area of four walls = 150 m²

• let breadth = b

Length is twice its breadth

• Therefore length = 2b

• Height = 4 m

Now curved surface area of cuboid = 2h(l+b)

$so \begin{gathered}2h(l+b)= C.S.A. \\\\\Rightarrow 2\times 4\times (2b+b)=150\\\\\Rightarrow 8\times 3b= 150\\\\\Rightarrow b= \dfrac{150}{8\times 3} = 6.25cm\end{gathered}$

• => 2h(l+b) = C.S.A.

• ⇒2×4×(2b+b)=150

• ⇒8×3b=150

• ⇒b = 8 × 3/150

• =6.25cm

length , l = 2b = 2 x 6.25 = 12.50 cm

Area of Floor = l x b= 6.25 x 12.50 = 78.125 cm²

Hence, area of the floor is 78.125 cm²

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hope it helps : )