the area of four walls of a room is 300 sq. m. if the height of the room is 6 m, what is the perimeter of the room.
Answers
Answered by
2
Answer:
250 m.
Step-by-step explanation:
area of 4 walls = 2(l + b) x h
According to question
300 sq. m . = 2(l+b) x h
300 = 2(l+b) x 6
300 / 6 = 2(l + b)
50 = 2(l + b)
50 / 2 = l + b
25 = l + b
now we have ( l + b ) = 25 m
perimeter of 1 wall = 2(l+b)
= 2 x 25
= 50 m
therefore perimeter of room = 5 x 50 m (perimeter of four wall + perimeter of ceiling)
= 250 m
Answered by
1
Answer:
50 m would be the perimeter of the room
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