the area of four Walls of a room is 51m². if the room is 5m long and 3.5m wide find the height of the room
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Given area of four walls is 51sq.m
therefore lateral surface area of cuboid is 51 Sq.m
2h(l+b) =51; L=5m b=3.5m
2h(5+3.5)=51
2h(8.5)=51
2h=51÷8.5
h=51÷(8.5×2)
h=51÷17
h=3
therefore,Height of the room = 3m
therefore lateral surface area of cuboid is 51 Sq.m
2h(l+b) =51; L=5m b=3.5m
2h(5+3.5)=51
2h(8.5)=51
2h=51÷8.5
h=51÷(8.5×2)
h=51÷17
h=3
therefore,Height of the room = 3m
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