The area of four walls of a room is 600 m square, the lengh and the height of room are 10 m
respectively. find the breadth and T.S.A. of room.
please help me
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Answer:
LSA
2(l+b)×h=600m²
2(10+b)×10=600m²
200+20b=600m²
20b=600-200
20b=400m²
b=20m
TSA=2lb+2bh+2hl
TSA= 2×20×10+2×20×10+2×10×10
TSA=400+400+200
TSA=1000m²
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