Question

The area of hall is 45m2. Its
length is 9 m find its
perimeter.​

Answer 1

Answer:

$= > area \: = l \times b \\ = > 45 {m}^{2} = 9 \times x \\ = > 45 \div 9 = x \\ = > 5 \\ breadth \: is \: \: 5m. \\ perimeter \: = 2(l + b) \\ = > 2(9 + 5) \\ = > 2 \times 14 \\ = > 28m \\ area \: is \: 28m$

Answer 2

Given :

• Area of hall = 45 m²

• Length of the hall = 9 m

To find :

• Perimeter of the hall

Solution :

Firstly, we will find the breadth of the wall. By using the following formula :-

Area of rectangle = l × b

where,

• l denotes the length

• b denotes the breadth

Substituting the given values :-

⟶ 45 = 9 × b

⟶ 45/9 = b

⟶ 5 = b

Therefore, the breadth of the rectangle = 5 m

Now, by using the following formula we will calculate the perimeter :-

Perimeter of rectangle = 2(l + b)

Substituting the given values :-

⟶ Periemter of hall = 2(9 + 5)

⟶ Perimeter of hall = 2(14)

⟶ Perimeter of hall = 28

Therefore, the perimeter of hall = 28 m