Question

the area of isosceles triangle whose equal sides are equal to 3 cm and other side is 4 cm ​

Answer 1

Answer:

Hence, the area would be 2√5 cm. The area of isosceles triangle whose equal sides are equal to 3 cm and other side is 4 cm.

Answer 2

Given: An isosceles triangle whose equal sides measure 3 cm each

          Measurement of other side = 4 cm

To find: Area of the triangle

Solution: According to the given question,

Measurement of equal sides = 3 cm

other side = 4 cm

.: Area of isosceles triangle = $\frac{1}{2}$[√($a^{2}$ - $b^{2}$/4) x b]

Here, b = base of the triangle (length of the side with different measurement)

         a = length of two equal sides

a = 3 and b = 4

Area = $\frac{1}{2}$[√($3^{2}$ - $4^{2}$/4) x 4]

        = $\frac{1}{2}$[√(9 - 16/4) x 4]

        = $\frac{1}{2}$[√(9 - 4) x 4]

        = $\frac{1}{2}$[√(5) x 4]

        = $\frac{1}{2}$ x 4$\sqrt{5}$ = 2$\sqrt{5}$

Therefore, area of the isosceles triangle is 2$\sqrt{5}$ $cm^{2}$.