Question

The area of Joe rectangular
farm is 5500 cm2, its width
is 11m find the length of the farm

Answer 1

Answer :-

• The length of Joe's rectangular farm is 500 m.

Given :-

• The area of Joe's rectangular farm is 5500 m².

• It's width is 11 m.

To find :-

• The length of Joe's rectangular farm.

Solution :-

• Here, the area and width of Joe's rectangular farm is given to us. We have to find it's length. Let's use the formula required for finding the area of a rectangle!

We know that :-

$\underline{ \boxed{\sf Area \: of \: a \: rectangle = Length \times Width}}$

Here,

• Area = 5500 m².
• Width = 11 m.

• Let the length be "l" m.

Substituting the given values in this formula,

$\longmapsto\bf5500 = l \times 11$

$\longmapsto\bf5500 = 11l$

$\longmapsto \bf \cancel{\dfrac{5500}{11}} = l$

$\longmapsto\overline{\boxed{\bf500 \: m = l}}$

________________________________

• Hence, the length of the farm is 500 m.

Answer 2

$❤️Solution❤️$

Given

• Area of Rectangular farm = 5500 m²
• Width of Rectangular farm= 11m

To Find

• Length of Rectangular farm

Formula Used

• $\boxed{\bf{Area~of~rectangle=length×width}}$

On Putting the value in Formula we get

$\\\sf {~~~~~:~\implies 5500m²=length×11m}$

$\sf {~~~~~:~\implies length = \dfrac{5500m²}{11m} }$

$\sf {~~~~~:~\implies length = \dfrac{ \xcancel{55} ^{5} 00m}{ \xcancel{11}} }$

$\sf {~~~~~:~\implies length = 500m}$

• $\\\\\text{\bf Hance, the length of }\\\text{\bf \underline{Rectangular farm= \pink{500m.}}}$

Diagram

$\\\begin{gathered}\begin{gathered}\begin{gathered}\tiny\begin{gathered} {\begin{gathered}\sf{11 \:m~~~}\huge\boxed{ \begin{array}{cc} \: \: \: {\tiny{\sf{Happy~Studying}}} \: \: \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \: \: \: \: \: \end{array}} \\ \: \: \: \: \: \sf{500 \: m~~~} \end{gathered}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$

$\\\\\\\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \bigstar \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Perimeter \: of \: rectangle = 2(l + b)}} \\ \\ \dashrightarrow \sf{Area \: of \: rectangle = length \: \times breadth }\\ \\ \dashrightarrow \sf{Perimeter \: of \: square = 4 \times side } \\ \\ \dashrightarrow \sf{Area \: of \: square =(side) ^{2} } \\ \\ \dashrightarrow \sf{Area \: of \: parallelogram = base \times height} \\ \\ \dashrightarrow \sf{Area \: of \: trapezium = \frac{1}{2}×sum \: of \: parallel \: side \: \times \: height }\\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$