Question

the area of Jupiter's disk is 1.606 × 10^10km². when Jupiter is 588 million kilometers from the earth, what is the solid angle distended by Jupiter rather earth​

Answer 1

Answer:

Answer:the exact answer is not possibly coveyd

Answer:the exact answer is not possibly coveyd of that question

Answer:the exact answer is not possibly coveyd of that question if you want posiible so it is below calculated by calculator because simply it is simplfied

Answer:the exact answer is not possibly coveyd of that question if you want posiible so it is below calculated by calculator because simply it is simplfiedExplanation:

Answer:the exact answer is not possibly coveyd of that question if you want posiible so it is below calculated by calculator because simply it is simplfiedExplanation:7.8 * 10000 km

Answer 2

Answer:

$Distance of Jupiter from the \\ Earth, D=824.7×106km</p><p> \\ </p><p> \\ Angular diameter 35.72′′ \\ =35.72×4.874×10−6rad</p><p></p><p> \\ Diameter of Jupiter = d </p><p></p><p> \\ Using the relation, </p><p></p><p> \\ θ = d/ D</p><p></p><p> \\ d=θ D = 824.7 x 109 x 35.72 x 4.872 x 10−6 \\  = 143520.76 x 103 = 1.435 x 105 Km </p><p></p><p>$

Explanation:

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