the area of of trapezium is 12 Sq. m and it's height is 3m find sum of its parallel sides
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8
HEY...
AREA OF TRAPEZIUM = 1/2*( SUM OF LENGTHS OF PARALLEL SIDES) * HEIGHT
HERE THE HEIGHT AND AREA IS GIVEN ....
12= 1/2(SUM OF PARALLEL SIDES)*3
24= 3* SUM OF PARALLEL SIDES
SUM OF PARALLEL SIDES= 24/3
SO
SUM OF PARALLEL SIDES= 8
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AREA OF TRAPEZIUM = 1/2*( SUM OF LENGTHS OF PARALLEL SIDES) * HEIGHT
HERE THE HEIGHT AND AREA IS GIVEN ....
12= 1/2(SUM OF PARALLEL SIDES)*3
24= 3* SUM OF PARALLEL SIDES
SUM OF PARALLEL SIDES= 24/3
SO
SUM OF PARALLEL SIDES= 8
I HOPE IT WILL HELP U MATE ☺❤☺
PLEASE MARK AS BRAINLIEST ❤☺❤
Answered by
10
area of trapezium =( a+b)/2xh
where a and b are the lengths of parallel sides
h is height of trapezium
hence * (a+b)/2xh=12
(a+b)/2x3=12
(a+b)/2 =4
(a+b) =8.. ans..
sum of parallel side is 8 m
where a and b are the lengths of parallel sides
h is height of trapezium
hence * (a+b)/2xh=12
(a+b)/2x3=12
(a+b)/2 =4
(a+b) =8.. ans..
sum of parallel side is 8 m
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