Physics, asked by nandanikumari4885, 7 months ago

The area of one end of a U-tube is 0.01 m^2 and that of the otherend is 1 m². When a force was applied on the liquid at the firstend, the force experienced at the other end was 20000 N. Whatwas the force applied on the liquid at the first end?​

Answers

Answered by Anonymous
1

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\huge{A}\small{1} = 0.01m²

\huge{A}\small{2} = 1m²

\huge{F}\small{1 }= ?

\huge{F}\small{2 }= 20000N

\dfrac{F1}{F2}=\dfrac{A1}{A2}

F1=F2×\dfrac{A1}{A2}

20000×\dfrac{0.01}{1}

=200N

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