Physics, asked by sonalssingh1773, 5 months ago

The area of one end of a U-tube is 0.01 square and that of the other end is 1 metre square when a force was applied on the liquid at the first end the force experienced at the other end was 20000 N . What was the force applied on the liquid at the first end

Answers

Answered by Anonymous
7

\LARGE\pink              { \underline{\underline{\sf{꧁ᗩᑎՏᗯᗴᖇ꧂}}}}

\huge{A}\small{1} = 0.01m²

\huge{A}\small{2} = 1m²

\huge{F}\small{1 }= ?

\huge{F}\small{2 }= 20000N

\dfrac{ᗩ1}{ᗩ2}=\dfrac{ᗩ1}{ᗩ2}

ᖴ1=ᖴ2×\dfrac{ᗩ1}{ᗩ2}

20000×\dfrac{0.01}{1}

=200N

Answered by Limafahar
5

♧︎︎︎ᴀɴsᴡᴇʀ♧︎︎︎

A1=0.01

A2=1

F2=20000N

F1=???

 \frac{F1}{F2}  =  \frac{A1}{A2}

 F1 = F2 \times  \frac{A1}{A2}

 = 20000 \times  \frac{0.001}{1}

200N

Similar questions