Question

The area of parallelogram determined by A=2i^+j^-3k^ and 12j^-2k^.

Answer 1

Answer:

Explanation:

Hope thse helps u to understand my ans

Answer 2

Answer:

Given,

A = 2i+3j and B = i+4j .

★ Area of paralleogram

=> A x B = (2i+3j+0k) x(i+4j+0k) 

• For  i component we have,

(3 * 0) -  (4 * 0) = 0

• For j component we have,

(0 * 2) - (1 * 0) = 0

• For k component we have,

(2 * 4) - (1 * 3) = 5.

Now take the magnitude of this vector to find the area of the parallelogram:

A * B = Whole root of 0^2 + 0^2 + 5^2

         = 0 + 0 + 5(Square and root will be cancelled)

         = 5 units.