the area of quadrant of a circle whose circumference is 22m is
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Answer:
9.625{cm}^{2}
Step-by-step explanation:
Given:
Circumference of cicrle = 22 cm
We know that
Circumference of circle = 2\pi r
22 cm = (2 × 22 × r)/7
7 cm = 2r
r = 3.5 cm
Area of quadrant = (\pi {r}^{2})/4
= ((22 × 3.5 × 3.5)/7)/4
= (11×3.5)/4
= 38.5/4
= 9.625 {cm}^{2}
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