Question

the area of quadrilateral ABCD is 20cm²and perpendicular on BD from opposite vertices are 1cm and 1.5cm. The length of BD is
(please give answer with correct explanation)​

Answer 1

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Answer 2

$\: \: \: \: \: \: \huge\sf \pmb{\orange {\underline \pink{\underline{\:Ꭺ ꪀ \mathfrak ꕶ᭙ꫀя \: }}}}$

$\sf \pmb{Area \: of \: Quadrilateral = 20}$

$\sf \: Let, \: the \: Length \: of \: BD \: (Diagonal) \: be \: \red x \: cm$

$\sf \: Then,$

$\star\sf \pmb{\mathfrak {\underline \red { Area \: (Quadrilateral \: \sf ABCD) = \mathfrak Area \: ∆ (ABD) + \mathfrak Area \: ∆(ACD)}}}$

$\sf Area \: of \: Quadrilateral = \frac{1}{2} \times (BD) \times (AC) +\frac{1}{2} \times (BD) \times (CM)$

$\: \: \: \: \: \sf \pink \implies \: 20( \frac{1}{2} \times x \times 1) \: + \: ( \frac{1}{2} \times x \times 1.5)$

$\: \: \: \: \: \sf \pink \implies\: 2.5x = 40$

$\: \: \: \: \: \sf\pink \implies \: x = \frac{400}{25}$

$\therefore \ \: \pink \implies\sf \pmb{\underline {\boxed { \sf \red{x = 16 cm}}}}$

$\sf \pmb {\underline{Note}} : Scroll \: right \: \: for \: clear \: view \: ➾$

$\: \: \: \: \: \huge\sf \pmb{\orange {\underline \pink{\underline{\:♛ Ꮇ༊ ꕶฬคᎶ ♛ \: }}}}$

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