The area of quadrilateral formed by the points (a,a),(-a,a),(a,-a),(-a,-a) is
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Answer:
2a²
Explanation:
- Area of quadrilateral=1/2[x1(y2-y3)+x2(y3-y1)
+3(y1-y2)
X1=-a
X2=a
X3=-a
:y1=a
Y2=-a
Y3=-a
Put in equation
Area of quadrilateral=1/2[-a(-a-(-a)) +a(-a-a) +(-a) (a-(-a)]
=1/2[-a(0)+a(-2a) -a(2a)]
=1/2[0-2a²-2a²]
=1/2(-2a²-2a²)
=1/2×-4a²
=4a²/2 =2a²
Cut the 4 by 2
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