The area of quadrilateral in which a diagonal is of length 10 cm and the offsets to the diagonal are of lengths 5cm and 3 cm is:-
a) 9 cm^2 b) 18 cm^2 c) 40 cm^2 d) 80 cm^2
Answers
Answer:
Area of quadrilateral ABCD is 55 \mathrm{cm}^{2}cm
2
Given:
Length of diagonal = 10 cm,
Length of perpendicular from B = 5 cm,
From D = 6 cm
To find:
Area of a quadrilateral
Solution:
Area of a quadrilateral ABCD = Area of triangle ABC + Area of triangle ADC
Area of a quadrilateral ABCD =\left(\frac{1}{2} \times A C \times 5\right)+\left(\frac{1}{2} \times A C \times 6\right)=(
2
1
×AC×5)+(
2
1
×AC×6)
\begin{gathered}\begin{array}{l}{=\left(\frac{1}{2} \times 10 \times 5\right)+\left(\frac{1}{2} \times 10 \times 6\right)}\\ \\ {=\left(\frac{50}{2}\right)+\left(\frac{60}{2}\right)} \\ \\{=25+30}\end{array}\end{gathered}
=(
2
1
×10×5)+(
2
1
×10×6)
=(
2
50
)+(
2
60
)
=25+30
Area of quadrilateral ABCD = 55 \mathrm{cm}^{2}cm
2
Answer:
maths to mere sir ke upar see nikalti hai sorry bro