Question

the area of quadrilateral is 120 cm^2 and the diagonal is 20 cm if the length of perpendicular from one vertex is 7 cm find the length of perpendicular from the other vertex ​

Answer 1

Answer:

5cm

Step-by-step explanation:

Given

Area = 120 cm²

BD = 20 cm

CN = 7 cm

Area of the field = Sum of area of the 4 triangles

i.e. ΔAMD + ΔAMB + ΔCNB + ΔCND

⇒ 120 = ( x DM x AM) + ( x BM x AM) + ( x BN x CN) + ( x DN x CN)

⇒ 120 = ( x DM x AM) + ( x BM x AM) + ( x BN x 7) + ( x DN x 7)

Replacing

BM = BD - DM = 20 - DM

and

DN = DB - NB = 20 - NB

⇒ 120 = ( x DM x AM) + ( x (20 - DM) x AM) + ( x BN x 7) + ( x (20 - NB) x 7)

⇒ 120 = ( x DM x AM) + 10 AM - ( x DM x AM) + ( BN) + 70 - ( BN)

⇒ 120 = 10 AM + 70

⇒ 50 = 10 AM

⇒ AM = 5

Answer 2

Answer:

from the given question answer is 5........