The area of rectangle carpet is 120m and its perimeter is 46 cm.The length of its diagonal is
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area of a rectangle = l × b
120 = l × b
l = 120/b
perimeter of a rectangle = 2(l+b)
46 = 2( 120/b + b)
23 = 120 +
23b = 120 +
- 23b + 120 = 0
- 15b - 8b + 120 = 0
b(b-15) - 8(b - 15)
(b-8)(b-15)
diagonal = √l^2 - b^2
√ 15×15 - 8×8
= 15 × 8
=120 cm
❤️
120 = l × b
l = 120/b
perimeter of a rectangle = 2(l+b)
46 = 2( 120/b + b)
23 = 120 +
23b = 120 +
- 23b + 120 = 0
- 15b - 8b + 120 = 0
b(b-15) - 8(b - 15)
(b-8)(b-15)
diagonal = √l^2 - b^2
√ 15×15 - 8×8
= 15 × 8
=120 cm
❤️
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