Question

The area of rectangle field is 24.03 area and its length is 54 metres. Find its breadth and perimeter​

Answer 1

$\huge\mathsf\pink{ANSWER}$

Breadth and perimeter of a rectangular field is 1800.85092 m and 3709.70184 m respectively.

Given, area of a rectangular field = 24.03 area

1 area = 4046.856 square meters

24.03 area = 4046.856 x 24.03 = 97245.94968 square meters

Length of a rectangular field = 54 m

Area = 97245.94968 square meters

=> Length x Breadth = 97245.94968 square meters

=> 54 m x Breadth = 97245.94968 square meters

=> Breadth =

$\frac{97245.94968}{54} = 1800.85092$

Perimeter = 2(Length + Breadth) = 2(54 + 1800.85092) = 2 x 1854.85092

Perimeter = 3709.70184 m

Hence, breadth and perimeter of a rectangular field is 1800.85092 m and 3709.70184 m respectively.

Answer 2

Given

• Area of rectangle field is 24.03 m²
• Length = 54 m

Explanation

We have to find the breadth by applying formula of Area as:-

Area of Rectangle = Length × Breadth

$\colon\longrightarrow{\sf{ 24.03 = 54 \times breath }} \\ \\ \colon\longrightarrow{\sf{ \cancel{ \dfrac{24.03}{54} } = breadth }} \\ \\ \colon\longrightarrow{\sf{ Breadth = 0.445 \ m}}$

Therefore, Breadth of the Rectangle is 0.445 m.

Now, we can find the perimeter by using length and breadth of the Rectangle as:-

$\colon\longrightarrow{\sf{ Perimeter_{(Rectangle)} = 2(l+b) }} \\ \\ \colon\longrightarrow{\sf{ Perimeter_{(Rectangle)} = 2(54+0.445) }} \\ \\ \colon\longrightarrow{\sf{ Perimeter_{(Rectangle)} = 2(54.445) }} \\ \\ \colon\longrightarrow{\sf{ Perimeter_{(Rectangle)} = 2 \times 54.445}} \\ \\ \colon\longrightarrow{\sf{ Perimeter_{(Rectangle)} = 108.89 \ m }}$

Hence,

${\underline{\sf{ The \ Perimeter \ of \ the \ Rectangle \ will \ be \ {\sf\large{108.89 \ m}} . }}}$