the area of rectangle get reduced by the 9 square units if the length is reduced by the 5 units and breadth is increased by 3 units
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Let length be l and breadth be b
A\Q,
(l-5)(b+3)=lb-9
lb-5b+3l-15=lb-9
3l-5b-15+9=0
3l-5b-6=0
I guess something is missing in this question
JimmyVV:
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Refer the attachment
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