Question

the area of rectangle gets reduce by 6 square units, if the length of the rectangle is reduced by 2 units and breadth increased by 1 units. If we increases the length by 3 units and reduce breadth by 1 units, the area increases by 9 square units. Find the perimeter of the rectangle.

PLEASE ANSWER​

Answer 1

Step-by-step explanation:

Let the length of the rectangle =x units

The breadth of the rectangle =y units

∴ Area of rectangle =xy sq. units

According to the first condition

⇒(x−5)(y+3)=xy−9

⇒xy+3x−5y−15=xy−9

⇒3x−5y=6........eq1

According to the second condition

⇒(x+3)(y+2)=xy+67

⇒xy+2x+3y+6=xy+67

⇒2x+3y=61.....eq2

Multiply eq1 by 3 and eq2 by 5

⇒9x−15y=18.......eq3

⇒10x+15y=305........eq4

Adding eq3 and eq4

⇒19x=323⇒x=17

Put x=17 in eq2

⇒2×14+3y=61

⇒3y=27⇒y=9

Hence, the length of the rectangle =17 units

The breadth of the rectangle =9 units

hope this solution will help you to solve this