Math, asked by rajputneha6973, 7 months ago

The area of rectangle gets reduced by 80 squnits if its length is reduced by 5 units and its breadth is increased by 2 units

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Answered by hritiksingh1
22

Answer:

✔️ verified answer

Let the length and breadth of the rectangle be a,b units respectively.

Then the area will be ab square units.

Now if the length of the rectangle is reduced by 5 units and breadth is increased by 2 units then new length and breadth will be (a−5) units and (b+2) units.

Then new area will be (a−5)(b+2).

Then according to the problem,

(a−5)(b+2)−ab=−80

or, 2a−5b=−70.......(1).

Now if length of the rectangle is increased by 10 units and breadth is decreased by 5 units then new length and breadth will be (a+10) units and (b−5) units.

Then new area will be (a+10)(b−5).

Then according to the problem,

(a+10)(b−5)−ab=50

or, 10b−5a=100

or, 2b−a=20

or, 4b−2a=40......(2).

Now adding (1) and (2) we get

−b=−30

or, b=30.

Putting the value of b in (1) we get, a=40.

Now a+b=40+30=70.

Answered by Anonymous
13

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