Question

the area of rectangle is 10 (2/3) Sq.cm. cm and the length is 4/9. find the width of the rectangle.​

Answer 1

L×B=Area

4/9×B=10(2/3)

B=10(2/3) ÷4/9

B=32/3×9/4

B=24

Answer 2

The correct answer is 24 cm.

Given: Area of rectangle = $10\frac{2}{3} Sq.cm$

Length = $\frac{4}{9} cm.$

To Find: Width of rectangle.

Solution:

Area of rectangle = $10\frac{2}{3} Sq.cm$ = $\frac{32}{3}$ sq.cm

Area = l*b

$\frac{32}{3}=\frac{4}{9}*b$

b = 24 cm

Hence, the width of rectangle is 24 cm.

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