the area of rectangle is 121(z square -25z+114)square units if one of the dimensions of the given rectangle is (11z-209) units find the other dimension
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area of rectangle=l×b
121(z square-25z+114)=(11z-209)×b
b=121z square-3025z+13834
Simply the equation,
b=z square-25z+114
b= z square-19z-6z+114
b=z(z-19)-6(z-19)
b=(z-19)(z-6)units
I DON'T KNOW IF THIS IS CORRCT BUT HOPE THIS HELPS
121(z square-25z+114)=(11z-209)×b
b=121z square-3025z+13834
Simply the equation,
b=z square-25z+114
b= z square-19z-6z+114
b=z(z-19)-6(z-19)
b=(z-19)(z-6)units
I DON'T KNOW IF THIS IS CORRCT BUT HOPE THIS HELPS
HarmanjotKaurGhuman:
thanks
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