The area of rectangle is 500 square cm and one of its side is 20 cm. Find the perimeter of the rectangle
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QUESTION➡
The area of rectangle is 500 square cm and one of its side is 20 cm. Find the perimeter of the rectangle ?
SOLUTION➡
Let the length be x cm
Area of rectangle = 500 cm^2
Breadth = 20 cm
_______________________________
Area of rectangle = Length × Breadth
500= x × 20
=> x = 25 cm
_____________________________
Perimeter of rectangle = 2(l+b)
= 2(25+20)
= 2× 45
= 90 cm
_____________________________
Therefore,
Perimeter of the rectangle is 90 cm
The area of rectangle is 500 square cm and one of its side is 20 cm. Find the perimeter of the rectangle ?
SOLUTION➡
Let the length be x cm
Area of rectangle = 500 cm^2
Breadth = 20 cm
_______________________________
Area of rectangle = Length × Breadth
500= x × 20
=> x = 25 cm
_____________________________
Perimeter of rectangle = 2(l+b)
= 2(25+20)
= 2× 45
= 90 cm
_____________________________
Therefore,
Perimeter of the rectangle is 90 cm
Answered by
0
Answer: Perimeter of rectangle is 90 cm.
Step-by-step explanation:
Let the one side be breadth(b)=20cm.
Area of rectangle=length(l)* breadth(b)
500 =l*20 [we put 20 in place of breadth]
l=500/20
length (l)=25cm
Perimeter of rectangle=2(length+breadth)
=2(25+20)cm
=2*45 cm
=90cm
Hope it will help you @
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