Question

The area of rectangle is 540² cm square and its length is 36 cm. find its width and perimeter.

Answer 1

area of rectangle =length x width
540 cm^2=36 cm x width
width =540/36=15cm

perimeter of rectangle =2 (length +width)
=2 (36+ 15)=2 x 51
perimeter of rectangle=102 cm

Answer 2

area of rectangle = length ×breadth
now 36×width = 540
width =540/36=15 c.m
perimeter of rectangle =2(length+ breadth)
so perimeter=2(15+36)=102 c.m