Question

The area of rectangle is 54m sq, whose length 3 m more than its width. find the dimension of the rectangle

Answer 1

solution.

Let the width= xm

Then, Length= (x+ 3 )m

ATQ,

=> x(x+3)= 54

=> x^2+ 3x= 54

=> x^2+ 3x - 54 = 0

=> x^2 + 9x - 6x - 54= 0

=> x(x+9) -6 (x+9)= 0

=> (x - 6) (x+ 9)=0

=> x - 6= 0 or, x+ 9= 0

=> x= 6 or x= -9

so, length can't be negative.

so, x= 6

Now, length= (3+6)= 9m

Breadth = 6m

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hope it helps you☺☺

Answer 2

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