The area of rectangle is 608 sq. Cm and the length is 32 m find its perimeter
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3
Answer:
perimeter of the rectangle is =102 m
Step-by-step explanation:
area is =608
area of rectangle is = l×b
l=32(given)
32×b=608
b=608/32
breadth = 19m
now perimeter of rectangle is =2(l+b)
=2(32+19)
=2(51)
=102m
Answered by
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Area of a rectangle =608
The length of a rectangle = 32
Perimeter of a rectangle = 2( l +b )
= 2( 608+32 )
=2(640)
= 320
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