Question

The area of rectangle is 608 sq. Cm and the length is 32 m find its perimeter

Answer 1

Answer:

perimeter of the rectangle is =102 m

Step-by-step explanation:

area is =608

area of rectangle is = l×b

l=32(given)

32×b=608

b=608/32

breadth = 19m

now perimeter of rectangle is =2(l+b)

=2(32+19)

=2(51)

=102m

Answer 2

Area of a rectangle =608

The length of a rectangle = 32

Perimeter of a rectangle = 2( l +b )

= 2( 608+32 )

=2(640)

= 320