Question

the area of rectangle is 640 m^2. Taking its length as X m. find in term of X, the width of rectangle. if the perimeter of the rectangle is 104m find is dimension

Answer 1

$perimeter \: \: 2(x + width) = 104 \\ width = 52 - x \\ area \: \: x \times (52 - x) = 640 \\ {x}^{2} - 52x + 640 = 0 \\ (x - 32)(x - 20) = 0 \\ x = 32 \: \: or \: \: 20 \\ since \: \: length \: \: is \: \: larger \\ length = 32 \\ width = 52 - 32 = 20$