Question

The area of rectangle is 9a²- 12a-32 cm².  Find its perimeter

Answer 1

Answer:

Perimeter of the rectangle = 12a - 8

Step-by-step explanation:

9a² - 12 - 32

= (3a)² - 24 + 12 - (4 × 8)

= (3a)² + (3a × (-8)) + (3a × 4) - (4 × 8)

= 3a(3a - 8) + 4(3a - 8)

= (3a - 8)(3a + 4)

Length of the rectangle = (3a + 4)

Breadth of the rectangle = (3a - 8)

Perimeter of the rectangle = 2(l + b)

= 2(3a + 4 + 3a - 8)

= 2(6a - 4)

= 12a - 8

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