Question

The area of rectangle is (X²+122 +39) sq.units what are
dimensions?​

Answer 1

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Area of Rectangle :- (x² + 122 + 39)

Now, here a = 1 , b = 122 , c = 39

Using the quadratic formula,

Discriminant = (b)² - 4ac

=> (122)² - 4(1)(39)

=> 14884 - 156

=> 14728

Now, since (b)² - 4ac > 0

∴ x = $\frac{-b± \sqrt{{b}^{2}-4ac}}{2a}$

=> $\frac{(-122)± \sqrt{{122}^{2}-4×1×39}}{2×1}$

=> $\frac{(-122)± \sqrt{14884-156}}{2}$

=> $\frac{(-122)± \sqrt{14728}}{2}$

=> $\frac{(-122)± 2\sqrt{2×7×263}}{2}$

=> $\frac{(-122)± 2\sqrt{3682}}{2}$

=> $\frac{2(-61± \sqrt{3682})}{2}$

=> $(-61)± \sqrt{3682}$

=> x = $(-61) + \sqrt{3682}$ & $(-61) - \sqrt{3682}$