Question

The area of rectangle is x2 -23 +132. If its breadth is (x-12), find its length.​

Answer 1

Answer:

ABCD is rectangle. Its diagonals meet at O. OA = 2x ‑ 1 and OD = 3x ‑ 2. Find x ABCD is rectangle. Its diagonals meet at O. OA = 2x ‑ 1 and OD = 3x ‑ 2. Find x 1 2 3 ‑1

Step-by-step explanation:

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Answer 2

$\large{\boxed{\red{\sf{A=l×b}}}}$

${\sf{x²-23x+132=l×(x-12)}}$

${\sf{l=(x²-23x+132)÷(x-12)}}$

${\sf{l=(x²-11x-12x+132)÷(x-12)}}$

${\sf{l=(x(x-11)-12(x-11))÷(x-12)}}$

${\sf{l=((x-11)(x-12))÷(x-12)}}$

${\red{\sf{l=(x-11)}}}$