Question

the area of rectangle is x² + 2x-35 sq units. find the length and breadth of the rectangle.






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Answer 1

Answer:

Area : 35y

Area : 35y 2

Area : 35y 2 +13y−12

Area : 35y 2 +13y−12Area of rectangle - Length×Breadth

Area : 35y 2 +13y−12Area of rectangle - Length×Breadth35y

Area : 35y 2 +13y−12Area of rectangle - Length×Breadth35y 2

Area : 35y 2 +13y−12Area of rectangle - Length×Breadth35y 2 +28y−15y

Area : 35y 2 +13y−12Area of rectangle - Length×Breadth35y 2 +28y−15y35y

Area : 35y 2 +13y−12Area of rectangle - Length×Breadth35y 2 +28y−15y35y 2

Area : 35y 2 +13y−12Area of rectangle - Length×Breadth35y 2 +28y−15y35y 2 +28y−15y

Area : 35y 2 +13y−12Area of rectangle - Length×Breadth35y 2 +28y−15y35y 2 +28y−15y7y(5y+4)−3(5y+4)

Area : 35y 2 +13y−12Area of rectangle - Length×Breadth35y 2 +28y−15y35y 2 +28y−15y7y(5y+4)−3(5y+4)(7y−3)(5y+4)

Area : 35y 2 +13y−12Area of rectangle - Length×Breadth35y 2 +28y−15y35y 2 +28y−15y7y(5y+4)−3(5y+4)(7y−3)(5y+4)∴ Length =(7y−3)

Area : 35y 2 +13y−12Area of rectangle - Length×Breadth35y 2 +28y−15y35y 2 +28y−15y7y(5y+4)−3(5y+4)(7y−3)(5y+4)∴ Length =(7y−3)Breadth =(5y+4)