Math, asked by siddhu4274, 10 months ago

The area of rectangle is192cm2 & perimeter is 56cm find the dimensions of rectangle

Answers

Answered by naavyya
0

Answer:

16 cm x 12 cm

Step-by-step explanation:

Attachments:
Answered by rajkvaid83
0

Answer:

Length = 16 cm

Breadth = 12 cm

Let the length of the rectangle be x cm an breadth be y cm

According to 1st condition

x × y = 192... ( 1 )

According to 2nd condition

x + y + x + y = 56

2x + 2y = 56

Divide throughout by 2

x + y = 28

x = 28 - y ... ( 2 )

Substitute 2 in 1

x + y = 192

28 - y × y = 192

28y - y^2 = 192

-y^2 + 28y - 192 = 0

-y^2 - 16y - 12y + 192 = 0

-y(y - 16 ) + 12 ( y - 16 ) = 0

( y - 16 ) ( -y +12 ) = 0

y + 16 = 0 or - y + 12 = 0

y = -16 or y = 12

y =/= - 16 breadth can't be negative

y = 12 cm

Substitute y = 12 cm in equation 2

x = 28 - y

x = 28 - 12

x = 16 cm

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