The area of rectangle is192cm2 & perimeter is 56cm find the dimensions of rectangle
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Answer:
16 cm x 12 cm
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Answer:
Length = 16 cm
Breadth = 12 cm
Let the length of the rectangle be x cm an breadth be y cm
According to 1st condition
x × y = 192... ( 1 )
According to 2nd condition
x + y + x + y = 56
2x + 2y = 56
Divide throughout by 2
x + y = 28
x = 28 - y ... ( 2 )
Substitute 2 in 1
x + y = 192
28 - y × y = 192
28y - y^2 = 192
-y^2 + 28y - 192 = 0
-y^2 - 16y - 12y + 192 = 0
-y(y - 16 ) + 12 ( y - 16 ) = 0
( y - 16 ) ( -y +12 ) = 0
y + 16 = 0 or - y + 12 = 0
y = -16 or y = 12
y =/= - 16 breadth can't be negative
y = 12 cm
Substitute y = 12 cm in equation 2
x = 28 - y
x = 28 - 12
x = 16 cm
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