the area of rectangle of length 21 cm and diagonal 29 cm is _________.
Answers
Answered by
1
Step-by-step explanation:
The area of a rectange = 420 cm^{2}cm
2
Step-by-step explanation:
Given,
The length of rectangle (l) = 21 cm and
The diagonal of of rectangle (d) = 29 cm
Let the breadth of rectangle = b cm
To find, the area of a rectange = ?
We know that,
The diagonal of of rectangle = \sqrt{l^{2}+b^{2}}
l
2
+b
2
⇒ \sqrt{21^{2}+b^{2}}
21
2
+b
2
= 29
Squaring both sides, we get
⇒ 21^{2}+b^{2}=29^221
2
+b
2
=29
2
⇒ b^{2}b
2
= 841 - 441 = 400
⇒ b^{2}b
2
= 20^{2}20
2
∴ The breadth of rectangle = 20 cm
The area of a rectange = Length(l) × Breadth (b)
= 21 cm × 20 cm
= 420 cm^{2}cm
2
Thus, the area of a rectange = 420 cm^{2}cm
2
Answered by
1
Answer:
420cm²
hope it is helpful
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