Math, asked by tejasg263pdv26g, 9 months ago

The Area of rectangle reduces by 20m^2, if its length is increased by 1m and the breadth is reduced by 2m. The area increases by 12m^2, if the length is reduced by 3m and breadth is increased by 4m. Find the dimensions of the rectangle.​

Answers

Answered by Anonymous
25

\boxed{\huge{\red{Answer}}}

\longrightarrowLet length of rectangle = x

\longrightarrowLet breadth of rectangle = y

\boxed{\huge{ATQ-1}}

\longrightarrow( x + 1 ) ( y - 2 ) = xy - 20m²

\longrightarrowxy - 2x + y - 2 = xy - 20

\longrightarrow -2x + y = - 18

\longrightarrow2x - y = 18 -------------( 1 )

\boxed{\huge{ATQ-2}}

\longrightarrow( x - 3 ) ( y + 4 ) = xy + 12m²

\longrightarrowxy + 4x - 3y - 12 = xy + 12

\longrightarrow 4x - 3y = 24 ------------ ( 2 )

\mathsfrack{Multiply\:by\:2\:to\:eqn\:(1)}

\longrightarrow4x - 2y = 36------------ ( 3 )

By comparing ( 3 ) and ( 2 )

4x - 3y = 24

4x - 2y = 36

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Sign changes

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\longrightarrow - y = - 12

\longrightarrow y = 12

Put y in eqñ ( 1 )

\longrightarrow2x - 12 = 18

\longrightarrow x = \frac{30}{2}

\longrightarrow x = 15

Length of rectangle\longrightarrow15m

Breadth of rectangle\longrightarrow12m

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