Question

the area of rectangle whose length is (3p-5) units and breadth is (2p+3)units --sq units​

Answer 1

Answer:

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Answer 2

• As per the data given in the question, we have to find the value of the expression.

           Given data:- Length of rectangle$=(3p-5)units.$

                               Breadth of rectangle$=(2p+3)units.$

           To find:-Value of given expression=?

         Solution:-

• We know that, all the angle of the rectangle is $90$ °.
• Formula of rectangle of are is

            Area of rectangle $=$ Length $\times$ Breadth

            Therefore,

             $Area \ of\ rectangle= (3p-5)\times(2p+3)\\Area \ of\ rectangle=6p^{2} -10p-3p-15\\Area \ of\ rectangle=6p^{2}- 7p-15.$

            Hence we will get the value $6p^{2} -7p-15\ sq\ units.$