Question

the area of rectangle whose length is 6 less than twice it width is 36​

Answer 1

Correct Question

Find The area of rectangle whose length is 6 less than twice to it's width is 36m

To Find:-

The area of the rectangle

Given:-

Length of the rectangle is 6 less than twice of the Width.

Width of the rectangle = 36m

Solution:-

step-by-step explanation:

So, By the problem

Let's first find the Length

here, Given

Length of the rectangle is 6 less than twice it's Width.

Width = 36 m

So,

Lenght = Twice Of Width - 6

= 36 × 2 - 6

= 72 - 6

= 66m

So, Length = 66 m

We know that

Area of the Rectangle = Length × Width

Area of the Rectangle = 66m × 36m

= 2376m²

Required Answer

$\therefore$ The area of the Rectangle = 2376m².

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Some Important Concepts

• Perimeter of the Rectangle

= 2 ( Length × Breadth )

• Volume of Cube = ( side )³
• Volume of Cylinder

= π ( radius ) × height

• Volume of cuboid = Length × Breadth × Height

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