Math, asked by shymalisingh1976, 4 months ago

The area of rectangle with length 2l²m and breadth 3lm² is​

Answers

Answered by Itzraisingstar
71

Answer:

Hey mate here is your answer:

Given:

length=\: 2l^2m,\\ breadth=\:3lm^2 ,

Solution:

→As you know area of rectangle = l × b.

→So,2l^2*3lm^2

6l^3m^2\:is\:the\:answer.

\boxed{\text{Hope It Helps You....}}

Please thank my answers

Answered by pulakmath007
9

SOLUTION

GIVEN

The length 2l²m and breadth 3lm²

TO DETERMINE

The area of the rectangle

EVALUATION

Here by the given

Length = 2l²m

Breadth = 3lm²

Hence the required area of the rectangle

= Length × Breadth

 \sf = 2 {l}^{2} m \times 3l {m}^{2}

 \sf = 2 \times 3 \times  {l}^{2 + 1}  \times  {m}^{1 + 2}

 \sf = 6  {l}^{3}   {m}^{3}

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