Question

The area of rectangular feild is 288m square if length of a feild is twice of wodth what should be the parameter of feild

Answer 1

let breadth isx

length is 2x

2x×x=288

2x^2=288

x^2=144

x=12

breadth is 12m

length is 24

perimeter=2(l+b)

2(12+24)

2(36)

72m

Answer 2

$\huge{\star{\underline{\boxed{\red{\sf{Answer :-}}}}}}{\star}$

★ Given :-

Length of a rectangular feild is 24 m.

Area of rectangular field is 288 m².

★ Assuming :-

Let the length of rectangular field be 2x.

So, the breadth of the rectangular feild be x.

★ Solution :-

We know that Area of rectangle is

$\LARGE{\underline{\boxed{\red{\sf{Area \: = \: l {\times}b}}}}}$

______________[Put Values]

→ 288 = 2x * x

→ 288 = 2x²

→ x² = 288/2

→ x² = 144

→ x =√144

→ x = 12

____________________________

So,

Length = 2x = 2(12) = 24 m

Breadth = x = 12 m

____________________________

${\underline{\boxed{\blue{\sf{Length\: = 24 m}}}}}$

${\underline{\boxed{\blue{\sf{Breadth\: = 12 m}}}}}$

Now,

We have to find perimeter of rectangular feild.

So,

$\LARGE{\boxed{\red{\sf{Perimeter = 2(l + b)}}}}$

______________[Put Values]

→ Perimeter = 2(12 + 24)

→ Perimeter = 2(36)

→ Perimeter = 72 m

${\underline{\boxed{\blue{\sf{Perimeter\: = 72 m}}}}}$