Question

The area of rectangular field is 10092 sq meter.Its length is three times as long as its width. Find its perimeter? Complete solution please

Answer 1

AREA OF RECTANGULAR FIELD = 10092 SQ
LENGTH = 3X
BREADTH =X
AREA OF RECTANGLE L×B
HERE 3X × X= 3X
SO, 3X=10092
X = 10092/3
x= 3364

LENGTH= 3X SO 3×3364= 10092
BREADTH= 3364
PERIMETER = 2(L+B)
SO, 2(10092+3364)
20910

Answer 2

Answer:

Concept:

• A quadrilateral with equal angles and parallel opposite sides is referred to as a rectangle.
• The length and width of any rectangle form serve as its two distinguishing attributes.
• The width and length of a rectangle, respectively, are its longer and shorter sides.

Area:

• The quantity of space occupied by a flat surface with a specific shape is referred to as the area.
• The "number of" square units are used to measure it.
• Area of Rectangle $=$ length $*$ breadth

Perimeter:

• The length of a rectangle's whole edge is known as its perimeter.
• It can be thought of as the rectangle's length and width added together.
• Perimeter of a Rectangle $=$ 2 (Length $+$ Breadth)

Given:

• The area of rectangular field is $10092 m^{2}$.
• Its length is three times as long as its width.

To Find:

We need to find its perimeter.

Solution:

Let x be breadth.

Since length is three times of its breadth.

∴ Length $= 3x$

$A = l*b$

⇒  $10092 = 3x *x$

⇒  $10092 = 3x^{2}$

⇒  $\frac{10092}{3} = x^{2}$

⇒  $3364=x^{2}$

⇒  $\sqrt{3364} =x^{2}$

⇒  $\sqrt{58*58} =x^{2}$

⇒  $58=x$

Length $= 3x =3*58=174m$

Breadth $= x = 58m$

Perimeter of a Rectangle = 2 (Length + Breadth)

⇒  $P=2(l+b)$

⇒  $P = 2(174+58)$

⇒  $P = 2(232)$

⇒  $P = 464$

Therefore, Perimeter of the given rectangular field is $464m$.

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