Question

The area of rectangular field is 260 m2. Had its length been 5m less and the breadth 2m more the field would have been in the shape of a square. Find the perimeter of the field​

Answer 1

Step-by-step explanation:

66 metre

step by step solution is given in above pic

Answer 2

The perimeter of the field​ is  66 m.

Explanation:

Let l be the length  and b be the breadth of the field.

As per given , we have

Area of rectangular field = length x breadth = lb = 260 m².

⇒ $b=\dfrac{260}{l}$   (1)

Also , its length been 5m less and the breadth 2m more the field would have been in the shape of a square.

i.e. l-5 = b+2  (∵Sides of square are equal)

$\Rightarrow\ l-b=7$

Put value of b from (1) , we get

$l-\dfrac{260}{l}=7\\\\\Rightarrow\ l^2-7l-260=0\\\\\Rightarrow\ l^2+13l-20l-260=0\\\\ (l+13)(l-20)=0\\\\\Rightarrow\ l= -13 \ or\ 20$

Since length cannot be negative , so l= 20 m

Now , b = $\dfrac{260}{20}=13\ m$

Perimeter of rectangular field = 2 (l+b)

=2(20+13) m

= 2(33) m

= 66 m

Hence, the perimeter of the field​ is 66 m.

# Learn more :

The area of a square field is 8649 m2. A rectangular field whose length is twice it's breadth had its perimeter equal to the perimeter of the square field. find the area of the rectangular field

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