Question

the area of rectangular field whose length is 895cm, is 6.7125 square m. find its perimeter.​

Answer 1

$\huge\mathbb{\underline{\underline{\blue{SOLUTION:-}}}}$

$\bold{Given}\begin{cases}\sf{length=895cm}\\ \sf{Area=6.7125m{}^{2}}\end{cases}$

$\huge\bold{\blue{To\:find:-}}$

The perimeter of rectangular field

$\bf{\underline{\underline{\red{According\:to\: Question:-}}}}$

• First find the width of rectangular field

$\sf {\underline{\purple{Area\:of\: rectangle=Length\times Breadth}}}$

Convert the area into cm

$\sf 1m{}^{2}=(100cm){}^{2}\\ \\ \sf \implies 1m{}^{2}=10000cm{}^{2}\\ \\ \sf\implies 6.7125m{}^{2}=67125cm{}^{2}$

$\sf Area=L\times Breadth\\ \\ \sf\leadsto 67125=895\times B\\ \\ \sf\leadsto \frac{\cancel{67125}}{\cancel{895}}=B\\ \\ \sf\implies 75=Breadth$

The breadth of rectangular field is 75cm

Now the perimeter

$\bf{\underline{\pink{Perimeter\:of\: rectangle=2(L+B)}}}$

$\sf Perimeter=2(75+895)\\ \\ \sf\implies Perimeter=2\times 970\\ \\ \sf\implies 1940cm$

The perimeter of rectangular field is 1940cm

#BAL

#answerwithquality

Answer 2

$\underline \mathbb{SOLUTION}$

$\underline \mathbb{GIVEN}$

LENGTH = 895cm

$area = 6.1725 {m}^{2}$

$\underline \mathbb{ATQ}$

》Area of rectangle = length × breadth

Convert area into cm.

》$1 {m}^{2} = 100 {cm}^{2}$

》$1 {m}^{2} = 10000cm { }^{2}$

》$6.7125 {m}^{2} = 67125 {cm}^{2}$

$area = lengh \times \: breadth$

=$67125 = 895 \times b$

=$\frac{67125}{895} = b$

=$75 = breadth$

》The breadth of rectangular field is 75 cm.

$\underline \mathbb{NOW}$

》The perimeter of rectangle is equals to 2( l+ b )

$perimeter = 2(75 + 895)$

=$perimeter = 2 \times 970$

$= > 1940cm$

》THE PERIMETER OF RECTANGULAR FIELD IS 1940 cm.

#BAL

#Answerwithquality