Question

The area of rectangular field whose length is twice its breadth is 4232m². Find the perimeter of the field​

Answer 1

Answer :-

• Perimeter of the field = 276m

To Find :-

• The perimeter of the field.

Given :-

• Area of rectangular field = 4232m²

• Length is twice it's breadth.

Step By Step Explanation :-

As we know the area of rectangular field whose length is twice its breadth is 4232m². We need to find the perimeter of rectangular field.

So let's do it !!

Let us consider the length as 2x and breadth as x.

Now as we know ⤵

$\boxed{ \underline{ \mathfrak{ \pink{Area_{(Rectangle)} = Length \times Breadth}}}}$

By substituting the values of length and breadth of rectangle.

$\implies\sf2x \times x = 4232 {m}^{2} \\ \\\implies\sf 2 {x}^{2} = 4232 \\ \\\implies\sf {x}^{2} = \cancel\cfrac{4232}{2} \\ \\ \implies\sf {x}^{2} = 2116 \\ \\\implies\sf x = \sqrt{2116} \\ \\\implies\bf x = 46$

x = 46

Now length will be 2x => 92m and breadth will be 46m

Let's calculate perimeter now !!

$\boxed{ \underline{ \mathfrak{ \green{Perimeter_{(Rectangle)} = 2(Length + Breadth)}}}}$

By substituting the actual values of length and breadth ⤵

$\implies\sf2(92 + 46) \\ \\ \implies\sf 2 \times 138 \\ \\ \implies\bf 276m$

Therefore perimeter of the field = 276m.

__________________________