The area of rectangular land of Suhas's is 500 sq. meter. If length of land is decreased by 3 metre and breadth is increased by 2 meter, then the land formed a square. Let us write by calculating the length and breadth of land of Suhas's.
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Answers
The length of the land is 25 m and the breadth of the land is 20 m respectively.
Explanation:-
Area of rectanglular land = 500 m²
When the length is decreased by 3 metre and the breadth is increased by 2 metre, the land forms a square.
The length and breadth of the land
Let the length be 'l' m
and the breadth be 'b' m
We know that,
=> Length × Breadth = Area
=> l × b = 500
Now,
New length = (l - 3) m
and new breadth = (b + 2) m
As it forms a square, The sides of square are the same. So :-
=> l - 3 = b + 2
=> l = b + 2 + 3
=> l = b + 5
Now,
Putting the value of l :-
=> l × b = 500
=> (b + 5) × b = 500
=> b² + 5b = 500
=> b² + 5b - 500 = 0
=> b² + (25 - 20)b - 500 = 0
=> b² + 25b - 20b - 500 = 0
=> b(b + 25) - 20(b + 25) = 0
=> (b - 20) (b + 25) = 0
Either, (b + 25) = 0 or, (b - 20) = 0
•b + 25 = 0
=> b = -25 (Neglected)
•b - 20 = 0
=> b = 20
Hence, the breadth of the rectangular field is 20 m.
Therefore:-
Hence, the length of length of the field is 25 m.
Answer:
________________________________
Consider the length be 'l' m
and the breadth be 'b' m
Length = Area
→ l × b = 500
________________________________
New length = (l - 3) m
New breadth = (b + 2) m
As it forms a square, The sides of square are the same. So :-
= l - 3 = b + 2
= l = b + 2 + 3
= l = b + 5
________________________________
★ Put the value of l :-
= l × b = 500
= (b + 5) × b = 500
= b² + 5b = 500
= b² + 5b - 500 = 0
= b² + (25 - 20)b - 500 = 0
= b² + 25b - 20b - 500 = 0
= b(b + 25) - 20(b + 25) = 0
= (b - 20) (b + 25) = 0
It can be (b + 25) = 0 or, (b - 20) = 0
• b + 25 = 0
= b = -25 (It is Neglected)
•b - 20 = 0
= b = 20
The breadth of the rectangular field is 20 m.
________________________________
★ Hence ;
= Length =
= Length =
= length = 25 m
The length of length of the field is 25 m.