The area of rectangular lawn is 5/16hectare the ratio of the base :height is 1:5 the height of lawn is
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Let the height and breadth be '5x' and 'x' respectively,
Area of a rectangle,
![= l*b = l*b](https://tex.z-dn.net/?f=%3D+l%2Ab)
![= x*5x = x*5x](https://tex.z-dn.net/?f=%3D+x%2A5x)
![= 5x^2 = 5x^2](https://tex.z-dn.net/?f=%3D+5x%5E2)
Now equate,
![5x^2 = 5/16 5x^2 = 5/16](https://tex.z-dn.net/?f=5x%5E2+%3D+5%2F16)
'5' is cacelled out,
![x^2 = 1/16 x^2 = 1/16](https://tex.z-dn.net/?f=x%5E2+%3D+1%2F16)
![x = 1/4 x = 1/4](https://tex.z-dn.net/?f=x+%3D+1%2F4)
Now height of the lawn,
![= 5x = 5x](https://tex.z-dn.net/?f=%3D+5x)
![= 5 * 1/4 = 5 * 1/4](https://tex.z-dn.net/?f=%3D+5+%2A+1%2F4)
![= 5/4 = 5/4](https://tex.z-dn.net/?f=%3D+5%2F4)
![= 1.25 = 1.25](https://tex.z-dn.net/?f=%3D+1.25+)
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_____________________________________________________________
Let the height and breadth be '5x' and 'x' respectively,
Area of a rectangle,
Now equate,
'5' is cacelled out,
Now height of the lawn,
Answered by
1
The answer is given below :
We know that,
1 hectare = 10000 m²
5/16 hectares = 3125 m²
The ratio of base : height = 1 : 5
Let, x be the common multiple.
Then, the base and the height of the rectangular line are x hectares and 5x hectares.
The area of the rectangular field
= base × height
= x × 5x m²
= 5x² m²
Given that,
5x² = 3125
=> x² = 625
So, x = 625, we take the positive value.
So, the base of rectangular lawn is 625 m and height be 3125 m.
Thank you for your question.
We know that,
1 hectare = 10000 m²
5/16 hectares = 3125 m²
The ratio of base : height = 1 : 5
Let, x be the common multiple.
Then, the base and the height of the rectangular line are x hectares and 5x hectares.
The area of the rectangular field
= base × height
= x × 5x m²
= 5x² m²
Given that,
5x² = 3125
=> x² = 625
So, x = 625, we take the positive value.
So, the base of rectangular lawn is 625 m and height be 3125 m.
Thank you for your question.
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